Question

Find p(0) and p (1) for the polonomial
P(y)=y²-y+1

Answer 1

p(0)=0^2-0+1=1

p(1)=1^2-1+1=1

p(2)=2^2-2+1=3

hope  it helps

Answer 2

Step-by-step explanation:

P(y)=y^2-y+1

P(0)=0^2-0+1=1

P(1)=1^2-1+1

=1-1+1

=1