Question

find p (0) and p (1) if p (x) =x^2+x-1​

Answer 1

Answer:

p(0)=0^2+0-1=0-1= -1

p(1)=1^2+1-1=1-0=1

Step-by-step explanation:

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Answer 2

Answer:

p(0) = -1, p(1) = 1

Step-by-step explanation:

=p(0)

= (0)^2+0-1

=0+0-1

=-1 .ans.

=p(1)

=(1)^2+1-1

=1+1-1

=1.ans.

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