find p(0)and p (1) if p(x)=x2+x-1
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hope this helps u
Step-by-step explanation:
p(x)=x2+x-1
p(0) = 0²+0-
p(0) = -1
p(1) = 1²+1-1
= 1+ 1-1
p(1)=1
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