Find p(0) and p(2) for each of the following a) p(t) = 3+t+2t2-t3
Answers
Answered by
2
Step-by-step explanation:
using p(0):-
- 3+0+2(0)^2-(0)^3
- 3+0+0-0
- =3
using p(2):-
- 3+2+2(2)^2-(2)^3
- 3+2+8-8
- =5
Answered by
0
Answer:
IF. p(t) = 3 + t + 2t^2 - t^3
then, p(2)= 3 + 2 + 2(2^2) - 2^3
= 3 + 2 + 8 - 8
= 5
IF. p(0) = 3 + 0 + 2(0^2) - 0^3
= 3 + 0 + 0 - 0
= 3
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