Math, asked by salmahcharaniya, 10 months ago

Find p(0) and p(2) for each of the following p(y)= y3-y2-y+1

Answers

Answered by aryan073

5

Step-by-step explanation:

p(0)=(0)³-(0)-(0)+1=1

p(2)=(2)³-(2)²-2+1=8-4-1=4-1=3

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