Question

Find P(0) and P(2) for the polynomial- P(y) = y2

-y+1​

Answer 1

Answer:

p(0)=1,p(2)=3

Step-by-step explanation:

for p(0)

p(y)=y^2-y+1

p(0)=0-0+1

p(0)=1

for p(2)

p(y)=y^2-y+1

p(2)=4-2+1

p(2)=3