Math, asked by kailashcmpatil, 5 hours ago

find :P(0) and P(2) for Y-Y^2+1​

Answers

Answered by kumarvimlesh1977
0

Answer:

P(0)=1 and P(2) = -1

Step-by-step explanation:

P(0) = 0-0^2+1 = 0+1 = 1

P(2) = 2-2^2+1 = 2-4+1 = -1.

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