Question

. Find p(0) if p(x) = x ^ 2 - 2x - 1 .

Answer 1

Step-by-step explanation:

p(0)

p(x) = x² - 2x - 1

p(0) = 0² - 2(0) - 1

• 0 - 0 - 1
• 0 - 1
• -1

Answer 2

Answer:

$p(x) = {x}^{2} - 2 x - 1 \\ p(0) = {0}^{2} - 2 \times 0 - 1 \\ = ( - 1) \: \:( ans.)$

Step-by-step explanation:

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