Question

find p (0) if p (y) = y² - y + 1​

Answer 1

Answer:

1 is the correct answer please go with it

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Answer 2

$\Huge{\textbf{\textsf{{\purple{Ans}}{\pink{wer}}{\color{pink}{:}}}}}$

$p(y) = {y}^{2} - y + 1 \\ put \: y = 0 \\ p(0) = ({0}^{2}) - 0 + 1 \\ = 1$