Question

Find p(0) of the polynomial p(y) = y2 – y - 3​

Answer 1

$\large\bold{\underline{\underline{Given:-}}}$

$p(y) = {y}^{2} - y - 3$

$\large\bold{\underline{\underline{To\:find:-}}}$

$p(0) = ?$

$\large\bold{\underline{\underline{Solution:-}}}$

For $p(0)$, just substitute $0$ for all values of $x$.

:⟼  $p(0) = {0}^{2} - 0 - 3$

:⟼  $p(0)= 0 - 0 - 3$

:⟼  $p(0)= - 3$

$\large\mathfrak{{\pmb{\underline{\red{Tornado77 }}{\red{❦}}}}}$