Question

Find p(0), p(1),and p(-1) for the each of the following polynomials:



(a) x²+2x+1. ( b) x²-1​

Answer 1

Answer:

a) x² +2x +1

p(0) = 0² + 2(0) + 1

= 1

p(1) = 1² + 2(1) + 1

= 1 + 2 + 1

= 4

p(-1) = (-1)² + 2(-1) + 1

= 1 -2 +1

= 2-2

=0

b) x² -1

p(0) = 0² -1

= -1

p(1) = 1² -1

= 1-1

= 0

p(-1) = (-1)² -1

= 1 -1

= 0

HOPE IT HELPS YOU!