Question

find p(0), P(1) and p(2) for each of the following:p(t)=2/3t^2+5/9t+4​

Answer 1

Step-by-step explanation:

p(0)=2/3(0)^2+5/9(0)+4=2/0+5/0+4

Can't determined because of 2/0 and 5/0.

p(1)=2/3(1)^2+5/9(1)+4=2/3+5/9+4=(6+5+36)/9

=47/9.

p(2)=2/3(2)^+5/9(2)+4=2/3×4+5/9×2+4

=2/12+5/18+4

=(6+10+144)/36=160/36=80/15=16/3.