Question

find p(0),p(1) and p(2) for each of the following: p(x)=(-x^2+5x+10)​

Answer 1

Answer:

just substitute x with 0,1 ,2

Step-by-step explanation:

p(0) = 10

p(1)= 14

P(2)= 16

Answer 2

Answer:

Step-by-step explanation:

Given, polynomial is

p(x) = 10x – 4x2 – 3

On putting x = 0,1 and – 2, respectively in Eq. (i), we get p(0) = 10(0)-4(0)2 -3 = 0-0-3= -3

p(1) = 10 (1) - 4 (1 )2 -3

= 10-4-3= 10-7= 3

and p(-2) =10 (-2)- 4 (-2)2 – 3

= -20-4×4-3 =-20-16-3=-39

Hence, the values of p(0), p(1) and p(-2) are respectively, -3,3 and – 39.