Question

Find p (0), p (1) and p (2) for each of the following polynomials:-
(0) p(y) = y2 - y +1
(ii) p(x) = x​

Answer 1

Answer:

$i) \: \: \: \: \: \: p(0) = 1 \: \: \: \: \: p(1) = 1 \: \: \: \: \: \: p(2) = 3 \\ \\ \\ ii) \: \: \: \: \: p(0) = 0 \: \: \: \: \: p(1) = 1 \: \: \: \: \: \: p(2) = 2$

Step-by-step explanation:

$i) \: \: \: \: \: \: p(y) = {y}^{2} - y + 1 \\ \\ p(0) = 0 - 0 + 1 = 1 \\ \\ p(1) = 1 - 1 + 1 = 1 \\ \\ p(2) = {2}^{2} - 2 + 1 = 4 - 2 + 1 = 3 \\ \\ \\ \\ ii) \: \: \: \: p(x) = x \\ \\ p(0) = 0 \\ \\ p(1) = 1 \\ \\ p(2) = 2$