Question

Find p(0),p(1)and p(2) for each of the following polynomials
(1).. p(y)=
${y}^{2}$
-y+1​

Answer 1

Step-by-step explanation:

p(0) = 0^2/-0+1 = 0/1 = 0

p(1) = 1^2/-1+1 = 1/0 = not defined

p(2) = 2^2/-2+1 = 4/-1 = -4

Answer 2

Answer:

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Step-by-step explanation:

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