Question

Find p(0),p(1) and p(2) for each of the following polynomials:
(ii) p (y) = y + y2 - 1
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Answer 1

Step-by-step explanation:

$(p = y) = y + {y}^{2} - 1 \\ = (p = 0) = 0 + {0}^{2} - 1 \\ 0 - 1 \\ - 1 \\ \\ = (p = 1) = 1 + {1}^{2} - 1 \\ = 2 - 1 \\ = 1 \\ \\ \\ = (p = 2) = 2 + {2}^{2} - 1 \\ = 2 + 4 - 1 \\ = 6 - 1 \\ = 5$

PLEASE MARK FOR BRAINLIEST

Answer 2

Answer:

p(0)= -1

p(1)= 1

p(2)= 5

Step-by-step explanation:

p(0)= 0+0^2-1

= 0+0-1

= -1

p(1)= 1+1^2-1

= 1+1-1

= 1

p(2)= 2+2^2-1

= 2+4-1

= 5

hope it helps