find p(0),p(1) and p(2) for each of the following polynomials (a)p(y)=9y^3+2y^2+y+7
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Answer:
p(0) is equal to 3,4,and 7
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Answer:
p(0)= 9*0^3+2*0^2+0+7
= 0+0+0+7
= 7
p(1) = 9*1^3+2*1^2+1+7
=9+2+1+7
= 19
p(2)= 9*2^3+2*2^2+2+7
= 9*8+2*4+2+7
= 72+8+2+7
= 89
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