Question

find p(0),p(1) and p(2) for each of the following polynomials
(i)p(y)=y2-y+1

Answer 1

Step-by-step explanation:

given

p(y)=y^2 -y+1

now

p(0)=(0)^2 -0+1

p(0)=0-0+1

p(0)=1

p(1)=(1)^2 -1+1

=1-1+1

0+1

=1

p(1)=1

p(2) =(2)^2 -2+1

=4-2+1

=2+1

=3

p(2)=3

therefore

p(0)=1 ,p(1)=1 ,p(2)=3 is answer

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Answer 2

Answer:

ok

Step-by-step explanation:

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