Find p(0), p(1) and p(2) for each of the following polynomials:
(i) p(y) = y^2– y + 1
(ii) p(t) = 2 + t + 2t^2– t^3
if you answer i will mark as brainliest........................
Answers
Answered by
1
Answer:
i. p ( 0 ) = 0^2 - 0 + 1
= 0 - 0 + 1
= 1
p ( 1 ) = 1^2 - 1 + 1
= 1 - 1 + 1
= 1
p ( 2 ) = 2^2 - 2 + 1
= 4 - 2 + 1
= 2 + 1
= 3
ii. p ( 0 ) = 2 + 0 + 2*0^2 - 0^3
= 2 + 0 + 0 - 0
= 2
p ( 1 ) = 2 + 1 + 2*1^2 - 1^3
= 2 + 1 + 2 - 1
= 5 - 1
= 4
p ( 2 ) = 2 + 2 + 2*2^2 - 2^3
= 2 + 2 + 8 - 8
= 4
hope it helps
Answered by
1
Answer:
1)
p(0)=1
p(1)=1
p(2)=3
2)
p(0)=2
p(1)=4
p(2)=4
Hope it helps
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