Question

Find p(0), p(1) and p(2) for each of the following polynomials:

(i) p(y)=y2−y+1​

Answer 1

Step-by-step explanation:

1.p(0)=(0)²-0+1

0+1

1

2 p(1)=(1)²-1+1

1-1+1

0+1

1

3.p(2)=(2)²-2+1

4-2+1

4-3

1

may it helps have a good day