Question

Find p(0),p(1) and p(2) for each of the following polynomials:
l.p(y)= y²-y+1
ll. p(t) =2+t+2t²-t³
lll. p(x) =x³
lV.p(x) =(x-1) (x+1)​

Answer 1

Answer:

(i) p (y) = y'-y+1

p(0)= 0'-0+1

p(0)=1

p(1)=1'-1+1

p(1)=1

p(2)=2'-2+1

p(2)=4-2+1

p(2)=1

rest parts are same