Question

Find p(0) p(1) and p(2) for each of the following polynomials p(t)=(t-1)(t+1)​

Answer 1

p(t)=(t-1)(t+1)

P(0)=(0-1)(0+1)

P(0)=(-1)(1)

P(0)=-1

p(t)=(t-1)(t+1)

P(1)=(1-1)(1+1)

P(1)=(0)(2)

P(1)=0

p(t)=(t-1)(t+1)

P(2)=(2-1)(2+1)

P(2)=(1)(3)

P(2)=3

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Answer 2

Answer:

-1, 0, 3

Step-by-step explanation:

Given:-

Equation p(t) = (t-1) (t+1)

To find :-

The solution of the above equation for p(0) , p(1) and p(2)

Solution:-

For p(0)

Put t =0

p(0) = (0-1) (0+1)

p(0) = -1 ×1

p(0) = -1

For p(1)

Put t = 1

p(1) = (1-1) (0+1)

p(1) = (0) (1)

p(1) = 0

For p(2)

Put t = 2

p(2) = (2-1) (2+1)

p(2) = (1) (3)

p(2) = 3....

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