Question

find p(0),p(1) and p(2) for each of the following polynomials.p(y)=y²-y+1​

Answer 1

Answer:

p(y) = y² - y +1

  p(0) = 0² - 0 +1

         = 1

 p(1) = 1² -1 +1

        = 1

p(2) = 2² - 2 +1

       = 3

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Answer 2

Answer:

3

Step-by-step explanation:

=p(0)2=(0)2=0+1=0-0+1=1

=p(1)2=(1)2=1+1=1-1+1=1

=p(2)2=(2)2=2+1=2+1=4-2+1=3

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