Question

Find p(0),p(1) and p(2) for each of the following polynomials
p(x)=x²-3x+2
with steps I want the answer friends​

Answer 1

p(x) = x^2-3x+2

p(0) = 0^2 + 3(0) + 2

      =  0 + 0 + 2

      = 2

p(1) = 1^2 + 3(1) + 2

     = 1  +  3  + 2

     = 4 + 2

     = 6

p(2) = 2^2 + 3(2) + 2

      =  4  +  6   +  2

      =      10     +  2

      =         12

HOPE IT HELPS YOU................................

Answer 2

Answer:

p(0) =0^2-3(0) +2

p(0) =0-0+2

p(0) =2

p(1) =1^2-3(1) +2

p(1) =1-3+2

p(1) =-2+2

p(1) =0

p(2) =2^2-3(2) +2

p(2) =4-6+2

p(2) =-2+2

p(2) =0

hope it helps