Question

Find p(0), p(1) and p(2) for each of the following polynomials p(y) = y2 - y + 1 ​

Answer 1

Answer:

p(0) = (0)2- 0+ 1

0 - 0+ 1

=1

p(1) = (1)2 - 1 +1

1 - 1 + 1

=1

p(2) = (2)2 -2 + 1

4 - 2 + 1

2+1

=3