Question

Find p
(0), p(1
) and p
(2) for each of the following polynomials p(t) =
2 + t + 2 t2 –t2​

Answer 1

Question :-

Find p(0), p(1) and p(2) for each of the following polynomials

p(t) = 2 + t + 2 t^2 –t^2.

Solution :-

=========================

putting t = 0

p(t) = 2 + t + 2 t^2 –t^2.

p(0) = 2 + 0 + 2 × 0^2 – 0^3

p(0) = 2 + 0 + 2 (0)^2 – 0^3

p(0) = 2 + 0 + 0 – 0

p(0) = 2

=========================

putting t = 1

p(t) = 2 + t + 2 t^2 –t^2.

p(1) = 2 + 1 + 2(1)^2 – (1)^3

p(1) = 2 + 1 + 2 + 1

p(1) = 4

=========================

putting t = 2

p(t) = 2 + t + 2 t^2 –t^2.

p(2) = 2 + 2 + 2 (2)^2 – 2^3

p(2) = 2 + 2 + 8 – 8

p(2) = 4 + 8 – 8

p(2) = 4.

==========================

Hope it helps you .

Answer 2

Find p

(0), p(1

) and p

(2) for each of the following polynomials p(t) =

2 + t + 2 t2 –t2