Question

find p(0), p(1) and p(2) for P(x) = (x-1) (x+1)​

Answer 1

Answer:

x^2-1

p(0)=-1

p(1)=0

p(2)3

Answer 2

Step-by-step explanation:

p(x)=(x-1)(x+1)

p(0)=(0-1)(0+1)= -1× 1= -1

p(1)=(1-1)(1+1)=0×2=0

p(2)=(2-1)(2+1)=1×3=3