find p(0),p(1) and p(2) for p(X)=x²-x+1
Answers
Answered by
3
Step-by-step explanation:
p (0) = 0-0+1
= 1
p (1) = 1-1+1
= 0
p (2) = 4-2+1
=3
please make my answer brainliest answer
Answered by
3
P(X)=x²-x+1
P(0)=(0)²-0+1
1
P(1)=(1)²-(1)+1
1-1+1
1
P(2)=(2)²-(2)+1
4-2+1
4-1
3
P(0)=1,p(1)=1,p(2)=3
Hope it will help you
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