find p(0),p(1) and p(2) for p(y)=9y³+2y²+y+7
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Answered by
2
P(0)=7
P(1)=19
P(2)=89
P(1)=19
P(2)=89
Answered by
0
p(y)=9y³ +2y² +y+7
p(0)=7
p(1)=19
p(2)=89
Hope it helps, pls mark as brainliest if u find it helpful☺
p(0)=7
p(1)=19
p(2)=89
Hope it helps, pls mark as brainliest if u find it helpful☺
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