Question

find p(0),p(1) and p(-2) for p(y) =(x-2) (x+2)​

Answer 1

Answer:

Hence, the values of p(0),p(1) and p(-2) are respectively,-4,-3 and 0.

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

p(y) = (x-2) (x+2)

§ p(0) = (0-2)(0+2)

Using identity (a-b)(a+b) = a² - b²

p(0) = 0²- 2²

p(0) = 0-4

p(0) = -4

§ p(1) = (1-2)(1+2)

Using identity (a-b)(a+b) = a² - b²

p(1) = 1²- 2²

p(1) = 1-4

p(1) = -3

§ p(-2) = [(-2) -2] [(-2) +2]

Using identity (a-b)(a+b) = a² - b²

p(-2) = (-2)²- 2²

p(-2) = 4 - 4

p(-2) = 0