Question

find p(0),p(1),and p(2) for p(y)=y²-y+1​

Answer 1

Step-by-step explanation:

(0) = (0)2 – 0 + 1

=>p(0) = 0 – 0 + 1

=> 1

Plug y = 1 we get

=>p(1) = (1)2 – 1 + 1

=>p(1) = 1 – 1 + 1

=> 1

Plug y = 2 we get

=>p(2) = (2)2 – 2 + 1

=>p(2) = 4 – 2 + 1

=> 3