Question

find p(0),p(1)and p(2) for polynomial p(y)=2+2ysquare-ycube​

Answer 1

Answer:

P(0) = 2

P(1) = 3

P(2) = 2

Step-by-step explanation:

We have,

P(y) = 2+ 2y^2-y^3

Now,

P(0)= 2+2(0)^2-(0)^3

P(0)= 2

Now,

P(1) = 2+2(1)^2-(1)^3

P(1) = 3

Now,

P(2) = 2+2(2)^2-(2)^3

P(2) = 2

Answer 2

Answer:

firstly,on putting the value of Y = O in equation

P(0)=2+2(0)square-(0)cube

P(0)=2+0-0

p(0)=2

on putting the value of y=1

p(1)=2+2(1)square-1cub

p(1)=2+2-1

p(1)=3

on putting the value of Y=2

P(2)=2+2(2)square-(2)cube

P(2)=2+8-8

P(2)= 2