Question

Find p(0),p(1) and p(2)for polynomial p(y)=y square-2y+1​

Answer 1

Step-by-step explanation:

P(y)=0

y^-2y+1

0^-2(0)+1

0-0+1

=1

P(y)=1

y^-2y+1

1^-2(1)+1

1-2+1

=0

P(y)=2

y^-2y+1

2^-2(2)+1

4-4+1

=1