Question

Find p(0),p(1) and p(2)for polynomial p(y)=y square-2y+1​

Answer 1

Answer:

$p(y)= {y}^{2} -2y+1$

$p(0)= {0}^{2} -2y+1$

$= - 2y + 1$

⠀⠀⠀⠀⠀⠀⠀⠀⠀

$p(1)= {1}^{2} -2y+1$

$= 1 - 2y + 1$

$= 2 - 2y$

⠀⠀⠀⠀⠀⠀⠀⠀⠀

$p(2)= {2}^{2} -2y+1$

$= 4-2y+1$

$= 5 - 2y$

Answer 2

Answer:

p(y) : y² - 2y + 1

Case I where p(0) means y = 0

• 0² + 2(0) + 1
• 0 + 0 + 1
• 1

Case II where p(1) means y = 1

• 1² - 2(1) + 1
• 1 - 2 + 1
• 2 - 2
• 0

Case III where p(2) means y = 2

• 2² - 2(2) + 1
• 4 - 4 + 1
• 0 + 1
• 1

Answers are 1 , 0 , 1