Question

Find p(0), p(-1), and p(+2) for the following polynomial.
p(b)=3b^2+b-1
whoever will give me the correct answer I will give thanks and I will follow them .​

Answer 1

Answer:

P(0)= -1 , P(-1)= 1 and P(2)= 13

Step-by-step explanation:

Firstly

P(0)= 3(0)²+0-1

= 0+0-1

=-1

Secondly

P(-1)= 3(-1)²+-1-1

= 3-2

=-1

Thirdly

P(2)= 3(2)²+2-1

= 12+1

=13