Question

Find P(0), P(1) and P(-2) for the following polynomials:

(a) P(x) = 10x – 4x2+3 (b) P(y) = (y+2) (y-2)​

Answer 1

Step-by-step explanation:

(a) P(x) =10x- 4x^2+3

Sol - P(0) = 10(0) - 4 (0)^2 +3

= 0 - 4×0+3

= 0-0+3

= 0+3

= 3

P(1) = 10(1) - 4(1)^2 +3

= 10 - 4×1 +3

= 10- 4 +3

= 10 - 7

= 3

P(2) = 10(2) - 4(2)^2 +3

= 20 - 4 ×4 +3

= 20 - 16 +3

= 20 - 19

= 1

(b) P(y) = (y+2)(y-2)

Sol- P(0) = (0+2)(0-2)

= (2)(-2)

= -4

P(1) = (1+2)(1-2)

= (3)(-1)

= -3

P(2) = (2+2)(2-2)

= (4)(0)

= 0

Hope it will help u...

Answer 2

Answer:

hey mate ... hope it helps you

plz mark me as brainliest