Question

Find p(0), p( 1) and p(-2) for the following polynomials
(i) p(x) = 10x – 4x2 – 3
(ii) p(y) = (y + 2)(y – 2)​

Answer 1

Answer:

1 Answer. Hence, the values of p(0), p(1) and p(-2) are respectively, -3,3 and – 39. Hence, the values of p(0),p(1) and p(-2) are respectively,-4,-3 and 0.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

(i) Given, polynomial is p(x) = 10x – 4x2 – 3 On putting x = 0,1 and – 2, respectively in Eq. (i), we get p(0) = 10(0)-4(0)2 -3  = 0-0-3  = -3 p(1) = 10 (1) - 4 1)2 -3 = 10-4-3 = 10-7 = 3 and p(-2) =10 (-2)- 4 (-2)2 – 3 = -20-4×4-3 =-20-16-3=-39

Hence, the values of p(0), p(1) and p(-2) are respectively, -3,3 and – 39. (ii) Given, polynomial is p(y) = (y+2)(y-2)

On putting y =0,1 and -2, respectively in Eq. (i), we get p(0) =(0+2)(0-2)= -4 p(1) = (1 + 2)(1-2) = 3 x (-1) = -3 and p(-2) = (-2 + 2)(-2 -2) =0 (-4) = 0 Hence, the values of p(0),p(1) and p(-2) are respectively,-4,-3 and 0.