Question

Find p(0),p(1) and p(2) for the given polynomial: p(y)=y²-y+1

Answer 1

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p(0)=0^2-0+1=1

p(1)=1^2-1+1=1

p(2)=2^2-2+1=3

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Answer 2

Answer:

p(0) =1

p(1) =1

p(2) =3

Step-by-step explanation:

It is given that p(y) is a polynomial function of y and the function is given by p(y) =y²-y+1.

Now, putting the value of y as 0, we get,

p(0)=0²-0+1 =1 (Answer)

Again, putting the value of y as 1, we get,

p(1) =1²-1+1=1 (Answer)

Now, again putting the value of y as 2, we get

p(2) =2²- 2+1 =3 (Answer)