Question

Find p(0), p(-1) and p(2) for the given
polynomials.
i. p(x) = x +7
ii. p(x) = 3x + 6
iii. p(y) = 7 - 3y2
iv. p(y) = 7y3
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Answer 1

We will put all the values of p in 1st part

p(x)=x+7

p(0)=0+7=7

p(-1)=-1+7=6

p(2)=2+7=9

p(x)=3x+6

p(0)=3(0)+6

=0+6=6

p(-1)=3(-1)+6

=-3+6=3

p(2)=3(2)+6

6+6=12

p(y)=7-3y2

p(0)=7-3(0)2

=7-0=7

p(-1)=7-3(-1)2

=7+3×2

=7+6=13

p(2)=7-3(2)2

=7-6×2

=7-12=-5

p(y)=7y3

p(0)=7(0)3

=0×3=0

p(-1)=7(-1)3

=-7×3=-21

p(2)=7(2)3

=14×3=42