Question

Find p(0) p(1) and p(2) for the polynomial
P(t)=2+t+2t-t²

Answer 1

Answer:

p(t) = 2 +t +2t -t²

a) t = 0

p(0) = 2+0+2×0 -(0)²

= 2 +0+0-0 = 2

b) now t= 1

p(1) = 2 + 1 + 2×1 -(1)²

= 2+1+2-1 = 2+2 = 4

c) now t= 2

p(2) = 2+2+2×2-(2)²

= 2+2+4-4 = 4

hope it will help you

Answer 2

Answer:

p(t) = 2 + t + 2t - t² = 2 + 3t - t²

p(0) = 2 + (3 × 0) - (0)² = 2 + 0 - 0 = 2 (Answer)

p(1) = 2 + (3 × 1) - (1)² = 2 + 3 - 1 = 5 - 1 = 4 (Answer)

p(2) = 2 + (3 × 2) - (2)² = 2 + 6 - 4 = 4 (Answer)

IF YOU LIKE THIS ANSWER, PLEASE MARK IT AS BRAINLIEST.