Question

find p(0) p(1) and p(2) for the polynomial px= (x-1) (x+2)​

Answer 1

Answer:

1. put x=0,

p(x)= (0-1) (0+2) = -1×2 = +2

2. put x=-1

p(x)= (-1-1) (-1+2) = -2×1 = -2

3. put x=-2

p(x)= (-2-1) (-2+2) = -3×0= 0

hope it helps....!!!

Answer 2

Answer:

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Step-by-step explanation:

Given : p(x)= (x-1)(x+2)

putting : x = 0

p (0) = (0-1)(0+2)

= (-1) (2)

= -2

putting : x = 1

p (1) =(1-1) (1+2)

= 0 (3)

= 0

putting : x= 2

p(2) = (2-1)(2+2)

= (1)(4)

=4