Find p (0), p(-1) and p(-2) for the polynomials p(x)=(x-1)(x+2).
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Answer:
p(0)=(0-1)(0+2)=(-1)(2)=-2
p(-1)=(-2)(-1+2)=-2
p(-2)=(-2-1)(0)=0
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p(0)=(0-1)(0+2)
=(-1)(2)
=(-2)
p(-1)=(-1-1)(-1+2)
= (-2)(1)
= (-2)
p(-2)=(-2-1)(-2+2)
=(-3)(0)
= 0
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