find p(0), p(1) and p(2) in p(y) =x3
Answers
Answered by
0
Answer:
p(0)=0³=1
p(1)=1³=1
p(2)=2³=8
Answered by
0
Answer:
p(0)= 0, p(1)= 1, p(2)= 8
Step-by-step explanation:
so simple put the value and get the answer
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