Math, asked by Taetae4, 2 days ago

find p(0), p(1) and p(2) in p(y) =x3​

Answers

Answered by meaarvind232
0

Answer:

p(0)=0³=1

p(1)=1³=1

p(2)=2³=8

Answered by shashipratapsingh24
0

Answer:

p(0)= 0, p(1)= 1, p(2)= 8

Step-by-step explanation:

so simple put the value and get the answer

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