find p(0) ,p(1) andp(2) for each of the following polynomials .p(y)=ysq. -y+1
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Answered by
1
Answer:
wdg-swbd-qpd I have been thinking about the last few
Answered by
1
Answer:
p(y) =y²-y+1
(1).p(0) =(0)²-0+1
=>p(0) =0-0+1
=>p(0) =0+1
=>p(0) =1
(2). p(1) =(1)²-1+1
=>p(1) =1-1+1
=>p(1) =0+1
=>p(1) =1
(3).p(2) =(2)²-2+1
=>p(2) =4-3
=>p(2) =1
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