Question

find p(0) p(1) for p( x )=x^2-x +1

Answer 1

ans of both ques is 1

Answer 2

$p(x) = {x}^{2} - x + 1$
$hence... \: p(0) = {0}^{2} - 0 + 1$
$= 0 - 0 + 1 = 1$
$and...p(1) = {1}^{2} - 1 + 1 \\ = 1$