Question

find P(0), p (-1) if p(y) = 4 + 3y- y^2 + 5y^2

Answer 1

Answer:

4,5

Step-by-step explanation:

given

p(y)=4+3y-y^2+5y^2

p(0)=4+3(0)-0+0

=4+0

=4

p(-1)=4-3-1+5

=5

Answer 2

Answer:

P(0)=4 and P(-1)=5

Step-by-step explanation:

First putting the value of y=0

Second putting the value of y= -1