Question

Find p(0),p(1), p(-2) for following polynomials
p(x)=10x-4xsquare-3

Answer 1

Answer:

Given, polynomial is

p(x) = 10x – 4x2 – 3

On putting x = 0, 1 and – 2, respectively in equation,

we get p(0) = 10(0) - 4(0)2 - 3

                    = 0 - 0 - 3 = -3

p(1) = 10 (1) - 4 (1 )2 -3

= 10-4-3 = 10-7 = 3

p(-2) =10 (-2)- 4 (-2)2 – 3

= -20-4×4-3 = -39

Hence, the values of p(0), p(1) and p(-2) are respectively, -3 , 3 and – 39.

Hope this helped you.... =))

Answer 2

Step-by-step explanation:

p(0)=10×(0)-4×(0)²-3

=0-0-3

=-3

p(1)=10×(1)-4×(1)²-3

=10-4-3

=3

p(-2)=10×(-2)-4×(-2)²-3

=20-4×-4-3

=20+16-3

=39

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