find p(0), p(1), p(2) for p(x) = 2+x+2x²-x³
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Answer:
p(0)=2
p(1)=3
p(2)=4
Step-by-step explanation:
CH-2 POLYNOMIALS CLASS 9
Answered by
0
Step-by-step explanation:
P(0)= 2+0+2(0)^2-(0)^3=2
P(1)=2+(1)+2-(1)^3= 3
P(2)=2+(2)+2(2)^2-(2)^3= 4
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