Find p(0), p(1), p(2) for p(x) = 2+x+2x²-x³
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Answer:
p(x) = 2 + x + 2x² - x³
p(0) = 2 + (0) + 2(0)² - (0)³
= 2
p(1) = 2 + 1 + 2(1)² - (1)³
= 5-1
= 4
p(2) = 2 + (2) + 2(2)² - (2)³
= 4 + 8 - 8
= 4
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