Question

find p(0), p(1), p(2)for polynomial p(y)=y^2-y+1​

Answer 1

Answer:

1,1,3

Step-by-step explanation:

p(x) =y^2-y+1

p(0) = 0-0+1

        =1

p(1)= 1 -1 +1

 = 1

p(2)= 4 - 2 +1

       = 3

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